Question

A track is in the form of a ring whose inner and outer circumferences are $88cm$ and $132m$ respectively. Find the width of the track.

Answer 1

Outer Circumference = 132 cm

=> Radius = Circumference / 2π

=> Radius = 132 / (2 × 22/7)

=> Radius = 132 / (44/7)

=> Radius = 132 × 7/44

=> Radius = 3 × 7

=> Radius = 21 cm

Inner Circumference = 88 cm

=> Radius = Circumference / 2π

=> Radius = 88 / (2 × 22/7)

=> Radius = 88 / (44/7)

=> Radius = 88 × 7/44

=> Radius = 2 × 7

=> Radius = 14 cm

Width of the ring = Outer Radius - Inner radius

= 21 - 14

= 7cm