A tractor is moving with a speed of $20$ km/hour, $x$ km ahead of a truck moving with a speed of $35$ km/hour. If it takes $20$ minutes for a truck to overtake the tractor, then what is $x$ equal to ?

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Solution

The correct option is A $5$ km
In 20 minutes, the truck covers a distance $= 35 \times \frac{20}{60} k m = \frac{35}{3} k m$

In 20 minutes, the tractor covers a distance = $20 \times \frac{20}{60} k m = \frac{20}{3} k m$

$∴ \frac{35}{3} = \frac{20}{3} + x$ $\Rightarrow x = \frac{15}{3} = 5 k m$

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A tractor is moving with a speed of 20 km/hour, x km ahead of a truck moving with a speed of 35 km/hour. If it takes 20 minutes for a truck to overtake the tractor, then what is x equal to ?

The correct option is A 5 kmIn 20 minutes, the truck covers a distance =35×2060km=353kmIn 20 minutes, the tractor covers a distance =20×2060km=203km∴353=203+x ⇒x=153=5km

A tractor is moving with a speed of $20$ km/hour, $x$ km ahead of a truck moving with a speed of $35$ km/hour. If it takes $20$ minutes for a truck to overtake the tractor, then what is $x$ equal to ?

The correct option is A $5$ km
In 20 minutes, the truck covers a distance $= 35 \times \frac{20}{60} k m = \frac{35}{3} k m$

In 20 minutes, the tractor covers a distance = $20 \times \frac{20}{60} k m = \frac{20}{3} k m$

$∴ \frac{35}{3} = \frac{20}{3} + x$ $\Rightarrow x = \frac{15}{3} = 5 k m$