Question

A trader bought a number of articles for $Rs1200$. Ten were damaged and he sold each of the remaining articles at $Rs2$ more than what he paid for it, thus getting a profit of $Rs60$ on the whole transaction. Taking no. of articles he bought as $x$, find $x$.

• A. $92$
• B. $85$
• C. $100$
• D. $56$

Answer 1

Answer: (C)

$100$

Let the no. of articles bought by the trader be $x$.

Total cost price $=$ Rs. $1200$

$\therefore$ CP of $1$ article $=\frac{1200}{x}$

$10$ articles were damaged, so remaining articles $=(x-10)$

New CP of $1$ article $=$ Rs. $\frac{1200}{x-10}$

SP of $1$ article = Rs. $(\frac{1200}{x-10}+2)$

Profit on entire transaction $=$ Rs. $60$

Now for $1$ article, Profit $=$ S.P - C.P

$\therefore \frac{60}{x-10}=\frac{1200}{x-10}+2-\frac{1200}{x}$

$\therefore$ $x=100$