A trader bought two horses for Rs 39,000. He sold one at a loss of 20% and another at a profit of 15%. If the selling price of each horse is same, then what are their cost price respectively?

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Solution

Let the cost price of one horse be $C$
Then cost price of other horse = $39000 - C$
According to question , $C \times \frac{8}{10} =$ ( $39000 - C$ )( $\frac{115}{100}$
Solving we get $C = 23000$
So, Cost price of one horse is Rs.23000 and cost price of other horse is Rs.16000

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A trader bought two horses for Rs 39,000. He sold one at a loss of 20% and another at a profit of 15%. If the selling price of each horse is same, then what are their cost price respectively?

Let the cost price of one horse be CThen cost price of other horse = 39000−CAccording to question , C×810= (39000−C)(115100Solving we get C=23000So, Cost price of one horse is Rs.23000 and cost price of other horse is Rs.16000

Let the cost price of one horse be $C$
Then cost price of other horse = $39000 - C$
According to question , $C \times \frac{8}{10} =$ ( $39000 - C$ )( $\frac{115}{100}$
Solving we get $C = 23000$
So, Cost price of one horse is Rs.23000 and cost price of other horse is Rs.16000