A trader has 600kgs of rice , a part of which he sells at 15% profit and the remaining quantity at 20% loss. On the whole , he incurs an overall loss of 6% .What is the quantity of rice he sold at 20% loss?

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Solution

Let the quantity of rice sold at $20$ % loss be $x$ Kg
And the cost price be $C / K g$
According to question + $x \times \frac{4}{5} C$ $+$ ( $600 - x$ ) $\times \frac{115}{100} C$ $= 600 \times \frac{94}{100} C$
Solving we get $x = 360$ Kg
Thus rice sold at 20% loss $= 360$ Kg

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A trader has 600kgs of rice , a part of which he sells at 15% profit and the remaining quantity at 20% loss. On the whole , he incurs an overall loss of 6% .What is the quantity of rice he sold at 20% loss?

Let the quantity of rice sold at 20% loss be x KgAnd the cost price be C/KgAccording to question + x×45C + (600−x) ×115100C =600×94100CSolving we get x=360KgThus rice sold at 20% loss =360Kg

Let the quantity of rice sold at $20$ % loss be $x$ Kg
And the cost price be $C / K g$
According to question + $x \times \frac{4}{5} C$ $+$ ( $600 - x$ ) $\times \frac{115}{100} C$ $= 600 \times \frac{94}{100} C$
Solving we get $x = 360$ Kg
Thus rice sold at 20% loss $= 360$ Kg