A train $110 m$ long is travelling at $60 k m / h r$ , In what time it will cross a cyclist moving at $6 k m / h r,$ in the same direction ?

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Solution

The relative velocity of the train will be,

$v = (60 - 6) k m / h r$

$= (54 \times \frac{5}{18}) m / s$
$= 15 m / s$
time taken by the train to cross the cyclist is,

$t = \frac{110}{15} sec$

$= 7.33 sec$

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A train 110m long is travelling at 60km/hr , In what time it will cross a cyclist moving at 6km/hr, in the same direction ?

The relative velocity of the train will be, v=(60−6)km/hr =(54×518)m/s =15m/stime taken by the train to cross the cyclist is, t=11015sec =7.33sec

A train $110 m$ long is travelling at $60 k m / h r$ , In what time it will cross a cyclist moving at $6 k m / h r,$ in the same direction ?

The relative velocity of the train will be,

$v = (60 - 6) k m / h r$

$= (54 \times \frac{5}{18}) m / s$
$= 15 m / s$
time taken by the train to cross the cyclist is,

$t = \frac{110}{15} sec$

$= 7.33 sec$