A train $110 m$ long is travelling at $60 k m / h r$ , In what time it will cross a cyclist moving at $6 k m / h r,$ in the opposite direction ?

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Solution

Relative speed is given as,
$v_{r} = 60 + 6 = 66 k m / h = 66 \times \frac{5}{18} = \frac{330}{18} = \frac{110}{6} m / s$

Time taken by cyclist to cross the train is given by

$t = \frac{110}{110 / 6}$

$t = 6 s$

Thus in $6$ seconds the cyclist will cross the train.

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A train 110m long is travelling at 60km/hr , In what time it will cross a cyclist moving at 6km/hr, in the opposite direction ?

Relative speed is given as,vr=60+6=66km/h=66×518=33018=1106m/s Time taken by cyclist to cross the train is given by t=110110/6 t=6s Thus in 6 seconds the cyclist will cross the train.

A train $110 m$ long is travelling at $60 k m / h r$ , In what time it will cross a cyclist moving at $6 k m / h r,$ in the opposite direction ?

Relative speed is given as,
$v_{r} = 60 + 6 = 66 k m / h = 66 \times \frac{5}{18} = \frac{330}{18} = \frac{110}{6} m / s$

Time taken by cyclist to cross the train is given by

$t = \frac{110}{110 / 6}$

$t = 6 s$

Thus in $6$ seconds the cyclist will cross the train.