A train $125$ m long passes a man running at $5$ kmph in the same direction in which the train is going in $10$ seconds. Find the speed of the train.

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Solution

Speed of the train relative to man = $(\frac{125}{10})$ m/sec
= $(\frac{25}{2})$ m/sec = $(\frac{25}{2} \times \frac{18}{5})$ km/hr = 45 km/hr
Let the speed of the train be x kmph Then relative speed = (x-5) km/hr
$∴$ x - 5 = 45 or x = 50 km/hr

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A train 125 m long passes a man running at 5 kmph in the same direction in which the train is going in 10 seconds. Find the speed of the train.

Speed of the train relative to man = (12510) m/sec= (252) m/sec = (252×185) km/hr = 45 km/hrLet the speed of the train be x kmph Then relative speed = (x-5) km/hr∴ x - 5 = 45 or x = 50 km/hr

A train $125$ m long passes a man running at $5$ kmph in the same direction in which the train is going in $10$ seconds. Find the speed of the train.

Speed of the train relative to man = $(\frac{125}{10})$ m/sec
= $(\frac{25}{2})$ m/sec = $(\frac{25}{2} \times \frac{18}{5})$ km/hr = 45 km/hr
Let the speed of the train be x kmph Then relative speed = (x-5) km/hr
$∴$ x - 5 = 45 or x = 50 km/hr