A train $210 m$ long took $12$ seconds to pass a $90 m$ long tunnel. Find the speed of the train.

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Solution

Total distance $= (250 + 90) n$
$= 300 m$
$∴$ time $= 12 s e c$
$∴$ speed $= \frac{d i s t a n c e}{t i m e}$
$∴$ speed $= \frac{300}{12}$
$∴$ speed $= 25 s e c$

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A train 210 m long took 12 seconds to pass a 90 m long tunnel. Find the speed of the train.

Total distance =(250+90)n=300 m∴ time =12 sec∴ speed =distancetime∴ speed =30012∴ speed =25 sec

A train $210 m$ long took $12$ seconds to pass a $90 m$ long tunnel. Find the speed of the train.

Total distance $= (250 + 90) n$
$= 300 m$
$∴$ time $= 12 s e c$
$∴$ speed $= \frac{d i s t a n c e}{t i m e}$
$∴$ speed $= \frac{300}{12}$
$∴$ speed $= 25 s e c$