A train $280 m$ long, running with a speed of 63 $k m /$ hr will pass a tree in

15 s e c

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16 s e c

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18 s e c

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20 s e c

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Solution

The correct option is B $16 s e c$
$S p e e d o f t r a i n = 63 (\frac{K m}{h r}) = (\frac{63 \cdot 100 m}{3600 s}) = 17.5 (\frac{m}{s}) B y p a s s i n g a t r e e, t r a i n w i l l h a v e t o c r o s s i t s o w n l e n g t h ∴ T i m e t a k e n = (\frac{280}{17.5}) = 16 s e c$

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