A train 300 metres long is running at a speed of 90 km/hr. How many seconds will it take cross a 200 metres long train running in the same direction at a speed of 60 km/hr?

70 sec

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60 sec

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50 sec

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None of these

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Solution

The correct option is B 60 sec
(b)
$H e r e L_{1} = 300 L_{2} = 200$
$s_{1} = 90 k m / h r a n d s_{2} = 60 k m / h r$

$s_{1} - s_{2} = 90 - 60 = 30 k m / h r = 30 \times \frac{5}{18} m / s$

$\frac{L_{1} + L_{2}}{s_{1} - s_{2}} = \frac{300 + 200}{30 \times \frac{5}{18}}$

$= \frac{500 \times 18}{30 \times 5} = 60 sec$

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