A train $400$ m long crosses a bridge $500$ m long in $90$ sec. Find the train in km/h ?

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Solution

To cross the bridge, the distance travelled by the train $= 400 m + 500 m = 900 m$

Time taken $= 90 s e c s$

$∴$ Speed of the train $= \frac{d i s t a n c e}{t i m e}$

$= \frac{900}{60}$

$= 15 m s^{- 1}$

$1 m = \frac{1}{1000} k m$ and $1 s e c o n d = \frac{1}{3600} h r s$

$= 15 \times \frac{1}{1000} \times 3600$ using $m s^{- 1} = \frac{m}{s}$

$= 15 \times \frac{3600}{1000}$

$= 15 \times \frac{18}{5} = 3 \times 18 = 54 k m p e r h r$

Hence the train travels at a speed of $54 k m p e r h r$

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