A train A travelled a distance of 120km in 3 hours whereas another train B travelled a distance of 180km in 4 hours. Which train travelled faster?

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Solution

Given Data:
Distance covered by train, $= 120 k m$
Time taken by train A, $= 3 h r$
Speed of train A, $= \frac{120 k m}{3 h r} = 40 k m {h r}^{- 1}$
Distance covered by train B, $= 180 k m$
Time taken by train, $= 4 h r$
Speed of train B, $= \frac{180 k m}{4 h r} = 45 k m h r^{- 1}$
Speed of train B is greater than train A, so train B is faster than A.

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5

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A train A travelled a distance of 120km in 3 hours whereas another train B travelled a distance of 180km in 4 hours. Which train travelled faster?

Given Data:Distance covered by train, =120km Time taken by train A,=3hr Speed of train A, =120km3hr=40kmhr−1 Distance covered by train B, =180km Time taken by train, =4hr Speed of train B, =180km4hr=45kmhr−1 Speed of train B is greater than train A, so train B is faster than A.