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Question
A train after travelling 50 km meet with an accident and then proceeds at 3/4th of its former speed and arrives at its destination 35 minutes late. Had an accident occurred 24 kms further, it would have reached destination only 25 minutes late. The speed of the train is ?
A train after travelling 50 km meet with an accident and then proceeds at 3/4th of its former speed and arrives at its destination 35 minutes late. Had an accident occurred 24 kms further, it would have reached destination only 25 minutes late. The speed of the train is ?
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Solution
The correct option is B 48 kmph
Train proceeds at 3/4 S where S is his usual speed means 1/4 decrease in the speed which will lead to 1/3 increase in the time.
[ As S *T = D, Speed is inversely proportional to time when distance is constant].
Now, the main difference come in those 24 km and the change in difference of time = 35 - 25 = 10 m
= 1 / 3 *T = 10 where T is the time required to cover the distance of (50 - 74) = 24 km
T = 30 min = 0.5 hours
Speed of the train = 24 / (0.5) = 48 kmph.
Train proceeds at 3/4 S where S is his usual speed means 1/4 decrease in the speed which will lead to 1/3 increase in the time.
[ As S *T = D, Speed is inversely proportional to time when distance is constant].
Now, the main difference come in those 24 km and the change in difference of time = 35 - 25 = 10 m
= 1 / 3 *T = 10 where T is the time required to cover the distance of (50 - 74) = 24 km
T = 30 min = 0.5 hours
Speed of the train = 24 / (0.5) = 48 kmph.
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