A train, blowing a whistle of frequency f, is standing in the railway yard. A person is running towards the engine. The frequency of the sound of the whistle as heard by the personn will be
A
greater than f
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B
less than f
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C
equal to f
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D
greater or less than f depending on the speed of the train.
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Solution
The correct option is A greater than f In the given situation , an observer is moving towards a stationary source of sound , therefore by Doppler's effect the apparent frequency f′ of whistle heard by person (observer) will be ,
f′=f(v+vov) ,
where , f= original frequency of sound ,
vo= velocity of observer ,
v= velocity of sound in air ,
It is clear from above formula that , f′>f ,the frequency of whistle heard by the person is greater than the original frequency of whistle .