The correct option is
C 9.24 A.M
Given that,
Two trains start at 7 A.M from their Starting Point
A train t1 goes from from Burdwan to Howrah in 6 Hrs
Another train t2 goes from Howrah to Burdwan in 4 Hrs
They will meet at ?
Step 1
Assume Distance between Burdwan and Howrah as a variable.
Let Distance between Burdwan and Howrah be x km
Step 2
Find the Distance Covered by the trains
Distance Covered by both the trains are equal, as both the trains are moving towards each other.
This Distance is equal to the distance between their Starting point and destination.
Distance Covered by train starting from Burdwan to Howrah = x km
Distance Covered by train starting from Burdwan to Howrah = x km
Step-3
Note the time taken by trains t1 and t2 to cover distance
Time taken by train starting from Burdwan to Howrah t1=6hrs
Time taken by train starting from Burdwan to Howrah t2=4hrs
Step-4
Find the Speed of trains t1and t2
We have,
speed=Distancetime
Speed of the train starting from Burdwan to Howrah s1=x6kmph
Speed of the train starting from Burdwan to Howrah s2=x4kmph
Step-5
Assume a variable for the time after starting time,for which both the trains are going to meet.
Let both the trains meets 'y' Hrs
Both the trains will meet at time (7+y) −(1)
Step-6
Express the distance covered by both the trains in terms of Speed and time
distance=speed×time
Distance Covered by the trains = (Speed of train t1)y + (Speed of train t2)y
Step-7
Substitute Values to obtain value of y
⟹x=(x6y+(x4y⟹x=x(y6+y4)⟹y(512=1⟹y=125hrs
Step-8
Express y in Mixed Fraction.
Y=225 hrs −(2)
Step-9
Express fractional part of Mixed fraction in minutes.
We have,
⟹25hrs=25×60=24min
Step-10
Substitute in (2)
Y=225hrs = 2 Hours 24 Minutes. −(3)
Step-11
Find the time at which both the trains will meet.
Substituting (3) in (1)
The time at which both the trains will meet = 7 AM + (2 Hours 24 min) = 9 Hours 24 Minutes AM