a train covered 36 3 by 4 kilometre in the first hour 40 2 by 5 km in second hour and 38 km in third hour. Find the total distance travelled by train in 3 hours

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Solution

$D e a r S t u d e n t, S o l u t i o n) I n f i r s t h o u r, d i s \tan c e = 36 \frac{3}{4} k m = \frac{147}{4} k m = 36.75 k m I n s e c o n d h o u r, d i s \tan c e = 40 \frac{2}{5} k m = \frac{202}{5} k m = 40.4 k m I n t h i r d h o u r, d i s \tan c e = 38 k m S o, t h e t o t a l d i s \tan c e t r a v e l l e d b y t r a i n i n 3 h o u r s = (36.75 + 40.4 + 38) k m = 115.15 k m R e g a r d s!$

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a train covered 36 3 by 4 kilometre in the first hour 40 2 by 5 km in second hour and 38 km in third hour. Find the total distance travelled by train in 3 hours

Dear Student,Solution)In first hour, distance=3634km=1474km=36.75kmIn second hour,distance=4025km=2025km=40.4kmIn third hour,distance=38kmSo, the total distance travelled by train in 3 hours=36.75+40.4+38km=115.15kmRegards!