A train covers a certain distance in 40 minutes if it runs at a speed of 54 kmph on an average. The speed at which the train must run to reduce the time of journey to 30 minutes will be

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Solution

The correct option is A 72
Speed = 54 kmph = $\frac{9}{10} k m / m i n$
$t_{1} = 40 m i n$
$\Rightarrow d = S p e e d \times t_{1}$
$d = \frac{9}{10} \times 40 \Rightarrow d = 36 k m s$
$∴$ when t = 30 min
speed = $\frac{36}{30} = \frac{6}{5} k m / m i n$
$∴$ Speed $= \frac{6}{5} \times 60$ kmph
$s p e e d = 72 k p h$

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A train covers a certain distance in 40 minutes if it runs at a speed of 54 kmph on an average. The speed at which the train must run to reduce the time of journey to 30 minutes will be

The correct option is A 72Speed = 54 kmph = 910km/mint1=40min⇒d=Speed×t1d=910×40⇒d=36kms∴ when t = 30 minspeed = 3630=65km/min∴ Speed =65×60 kmph speed=72kph