A train covers a distance of 480 km at a uniform speed. If speed had been 8km /hr less then it would have taken 3 hours more to cover the same distance. Find the usual speed of the train.
Distance travelled by the train = 480 km
Let the speed of the train be x kmph
Time taken for the journey = 480/x
Given speed is decreased by 8 kmph
Hence the new speed of train = (x – 8) kmph
Time taken for the journey = 480/(x – 8)
480x−8−480x=3
480(x−x+8)x(x−8)
480×83=x2−8x
1280=x2–8x
x2–8x–1280=0
On solving we get x = 40
Thus the speed of train is 40 kmph