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Byju's Answer
Standard VII
Mathematics
Comparing Quantities : Introduction
A train cover...
Question
A train covers a distance of 670 km in 6h 5 min.If it covers the first 390 km of the journey at 90 km/h,find its speed for rest of the journey?
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Solution
Dear student,
T
o
t
a
l
D
i
s
tan
c
e
=
670
k
m
C
a
s
e
1
H
e
c
o
v
e
r
s
d
i
s
tan
c
e
=
390
k
m
s
p
e
e
d
=
90
k
m
/
h
r
T
i
m
e
t
a
k
e
n
=
d
i
s
tan
c
e
s
p
e
e
d
=
390
90
=
4
.
34
h
r
=
4
h
r
+
0
.
34
×
60
m
i
n
=
4
h
r
20
m
i
n
B
u
t
w
e
k
n
o
w
t
o
t
a
l
t
i
m
e
t
a
k
e
n
=
6
h
5
m
i
n
∴
T
i
m
e
t
a
k
e
n
i
n
2
n
d
c
a
s
e
=
T
o
t
a
l
t
i
m
e
-
T
i
m
e
t
a
k
e
n
i
n
1
s
t
c
a
s
e
=
6
h
05
m
i
n
-
4
h
r
20
m
i
n
=
6
×
60
m
i
n
+
05
m
i
n
-
4
×
60
m
i
n
+
20
m
i
n
=
360
m
i
n
+
05
m
i
n
-
240
m
i
n
+
20
m
i
n
=
365
m
i
n
-
260
m
i
n
=
105
m
i
n
C
o
n
v
e
r
t
i
n
g
105
m
i
n
i
n
t
o
h
r
105
60
h
r
=
1
.
75
h
r
∴
T
i
m
e
t
a
k
e
n
i
n
2
n
d
c
a
s
e
=
1
.
75
h
r
D
i
s
tan
c
e
i
n
2
n
d
c
a
s
e
=
t
o
t
a
l
d
i
s
tan
c
e
-
d
i
s
tan
c
e
i
n
1
s
t
c
a
s
e
=
670
-
390
=
280
k
m
S
p
e
e
d
i
n
2
n
d
c
a
s
e
=
D
i
s
tan
c
e
i
n
2
n
d
c
a
s
e
T
i
m
e
t
a
k
e
n
i
n
2
n
d
c
a
s
e
=
280
1
.
75
=
160
k
m
/
h
r
Regards
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Similar questions
Q.
A train covers a distance of
90
km at a uniform speed. Had the speed been
15
km/hr more, it would have taken
30
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Q.
A train covers a distance of 90 km at a uniform speed. Had the speed been 15 km/hour more, it would have taken 30 minutes less for a journey. Find the original speed of the train.
