A train is at rest- It accelerates for a time t1 at a uniform rate - and the comes to rest under a uniform retardation rate - in time- t2- t1t2 is equal to

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Standard IX

Physics

Second Equation of Motion

A train is at...

Question

A train is at rest. It accelerates for a time $t_{1}$ at a uniform rate $α$ and the comes to rest under a uniform retardation rate $β$ in time. $t_{2}$ . $\frac{t_{1}}{t_{2}}$ is equal to

\frac{β}{α}

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\frac{α + β}{α}

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\frac{α + β}{β}

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α β

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Solution

The correct option is A $\frac{β}{α}$
Initially train is at rest.
From the 1st equation of motion,
$v = u + a t$
$v = 0 + a t$
$v = a t$
From the above equation,
$α t_{1} = β t_{2}$
$\frac{t_{1}}{t_{2}} = \frac{β}{α}$
The correct option is A.

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A train is at rest. It accelerates for a time t1 at a uniform rate α and the comes to rest under a uniform retardation rate β in time.t2. t1t2 is equal to

The correct option is A βαInitially train is at rest.From the 1st equation of motion,v=u+atv=0+atv=atFrom the above equation,αt1=βt2t1t2=βαThe correct option is A.

A train is at rest. It accelerates for a time $t_{1}$ at a uniform rate $α$ and the comes to rest under a uniform retardation rate $β$ in time. $t_{2}$ . $\frac{t_{1}}{t_{2}}$ is equal to

The correct option is A $\frac{β}{α}$
Initially train is at rest.
From the 1st equation of motion,
$v = u + a t$
$v = 0 + a t$
$v = a t$
From the above equation,
$α t_{1} = β t_{2}$
$\frac{t_{1}}{t_{2}} = \frac{β}{α}$
The correct option is A.