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Question

A train is moving along a straight line with a constant acceleration a. A boy standing in the train throws a ball forward with a speed of 10m/s, with respect to the train at an angle of 600 to the horizontal. The boy has to move forward by 1.15m inside the train to catch the ball back at the initial height. The acceleration of the train, in m/s2, is:

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Solution

The correct option is **A** 5

Ball performs parabolic motion,

For vertical motion,

s=ut−12gt2

∴0=10sin60ot−12×10×t2

∴t=√3s

For horizontal motion,

s=ut+12at2

∴1.15=10cos60o×√3−12a(3)

∴a=5m/s2

Ball performs parabolic motion,

For vertical motion,

s=ut−12gt2

∴0=10sin60ot−12×10×t2

∴t=√3s

For horizontal motion,

s=ut+12at2

∴1.15=10cos60o×√3−12a(3)

∴a=5m/s2

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