A train is moving at $30 m s^{- 1}$ in still air. The frequency of the locomotive whistle is $500$ Hz and the speed of sound is $345$ $m s^{- 1}$ . The apparent wavelengths of sound in-front of and behind the locomotive are respectively.

0.65

0.73

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0.63

0.75

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0.60

0.85

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0.60

0.75

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Solution

The correct option is A $0.65$ m, $0.73$ m
$S p e e d o f t r a i n = 30 \frac{m}{s}$

$S p e e d o f s o u n d = 345 \frac{m}{s}$

$S p e e d o f t r a i n = 10 \frac{m}{s}$

$F r e q u e n c y = 500 H z$

$v^{'} = v + v_{w i n d} = 345 + 10 = 355 \frac{m}{s}$

$λ^{'} = \frac{v^{'} - v_{s}}{f} = \frac{355 - 30}{500} = 0.65 m$

$v^{'} = v - v_{w i n d} = 345 - 10 = 335 \frac{m}{s}$

$λ^{'} = \frac{v^{'} + v_{s}}{f} = \frac{355 + 30}{500} = 0.73 m$

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A train is moving at 30ms−1 in still air. The frequency of the locomotive whistle is 500Hz and the speed of sound is 345 ms−1. The apparent wavelengths of sound in-front of and behind the locomotive are respectively.

The correct option is A 0.65m, 0.73mSpeedoftrain=30msSpeedofsound=345msSpeedoftrain=10msFrequency=500Hzv′=v+vwind=345+10=355msλ′=v′−vsf=355−30500=0.65mv′=v−vwind=345−10=335msλ′=v′+vsf=355+30500=0.73m

A train is moving at $30 m s^{- 1}$ in still air. The frequency of the locomotive whistle is $500$ Hz and the speed of sound is $345$ $m s^{- 1}$ . The apparent wavelengths of sound in-front of and behind the locomotive are respectively.