A train is moving at a speed of $40 k m / h$ at $10.00$ a.m and at $50 / k m / h$ at $10.15$ a.m. Assuming that the train moves along a straight track and the acceleration is constant, find out the value of the acceleration.

300 k m / h^{2}

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40 k m / h^{2}

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350 k m / h^{2}

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250 k m / h^{2}

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Solution

The correct option is B $40 k m / h^{2}$
$u = 40 k m p h, v = 50 k m p h, t = 0.25 h$
using : $v = u + a t$
$a = \frac{50 - 40}{0.25}$
$a = 40 k m p / h^{2}$

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A train is moving at a speed of 40 km/h at 10.00 a.m and at 50/km/h at 10.15 a.m. Assuming that the train moves along a straight track and the acceleration is constant, find out the value of the acceleration.

The correct option is B 40 km/h2u=40kmph,v=50kmph,t=0.25husing : v=u+ata=50−400.25a=40kmp/h2

A train is moving at a speed of $40 k m / h$ at $10.00$ a.m and at $50 / k m / h$ at $10.15$ a.m. Assuming that the train moves along a straight track and the acceleration is constant, find out the value of the acceleration.

The correct option is B $40 k m / h^{2}$
$u = 40 k m p h, v = 50 k m p h, t = 0.25 h$
using : $v = u + a t$
$a = \frac{50 - 40}{0.25}$
$a = 40 k m p / h^{2}$