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Standard XII

Physics

Direction of Friction

A train is mo...

Question

A train is moving on a track at 30 m/s. A ball is thrown from it perpendicular to the direction of motion at 30 m/s at $45^{0}$ from horizontal. Find the distance of ball from the point of projection when it strikes the ground.

90 m

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90 \sqrt{3} m

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60 m

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30 \sqrt{3} m

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Solution

The correct option is D 90 m
The horizontal range $R = \frac{u^{2} sin 2 θ}{g} = \frac{(30)^{2} sin 90}{10} = 90$ m
(As we measure the distance with respect to the frame of train so velocity of train will not effect on the distance )

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A train is moving on a track at 30 m/s. A ball is thrown from it perpendicular to the direction of motion at 30 m/s at 450 from horizontal. Find the distance of ball from the point of projection when it strikes the ground.

The correct option is D 90 mThe horizontal range R=u2sin2θg=(30)2sin9010=90 m(As we measure the distance with respect to the frame of train so velocity of train will not effect on the distance )

A train is moving on a track at 30 m/s. A ball is thrown from it perpendicular to the direction of motion at 30 m/s at $45^{0}$ from horizontal. Find the distance of ball from the point of projection when it strikes the ground.

The correct option is D 90 m
The horizontal range $R = \frac{u^{2} sin 2 θ}{g} = \frac{(30)^{2} sin 90}{10} = 90$ m
(As we measure the distance with respect to the frame of train so velocity of train will not effect on the distance )