A train is moving with a speed of $40 m s^{- 1}$ . On applying the brakes, it comes to rest in $20 s$ . What is the magnitude of average acceleration of the train?

2 m s^{- 2}

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3 m s^{- 2}

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4 m s^{- 2}

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5 m s^{- 2}

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Solution

The correct option is A $2 m s^{- 2}$
Given:
Initial velocity: $u = 40 m s^{- 1}$
Final velocity: $v = 0 m s^{- 1}$ (train is coming to rest)
Time taken: $t = 20 s$ .
Let the average acceleration be $a$

Acceleration is defined as the rate of change of velocity.
$a = \frac{v - u}{t}$
$a = \frac{0 - 40}{20} = - 2 m s^{- 2}$
(negative sign denotes that the train is decelerating)

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An object moving with a uniform velocity of $40 m s^{- 1}$ comes to rest in $10 s$ . What is the acceleration?

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v_{x} = 3 {ms}^{- 1}, v_{y} = 4 {ms}^{- 1}, a_{x} = 2 {ms}^{- 2}

a_{y} = 1 {ms}^{- 2}

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