A train is traveling at a speed of 90 km per hour- Brakes are applied so as to produce a uniform acceleration of -0-5 metre per second square- Find how far the train will go before it is brought to rest-

Here, Initial speed u = 90km/h = 90 x1000m/60*60 s = 25 m/s Final speed v = 0, Acceleration a = 0.5 m/s sq. Let the distance covered = s Since, v2 ...

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Standard IX

Physics

Derivation of Position-Velocity Relation by Graphical Method

A train is tr...

Question

A train is traveling at a speed of 90 km/h. Brakes are applied so as to produce a uniform acceleration of -0.5 meters per second square. Find how far the train will go before it is brought to rest.

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Solution

Given,
Initial speed u = 90 km/h = 90×5/18=25 m/s
Final speed v = 0,
Acceleration a = -0.5 m/s²
Let the distance traveled by the train before stopping = s
From the equation of motion
We know,
v²=u²+2as
Putting all the values
0²=25²−2×0.5×s
After solving
s=625m

Hence distance traveled by train before stopping is 625 m

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