A train is travelling at constant speed of $40 {m s}^{- 1}$ on a circular track of radius 120 m. Centripetal acceleration of the train is:

\frac{40}{7} {m s}^{- 2}

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\frac{40}{3} {m s}^{- 2}

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40 {m s}^{- 2}

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30 {m s}^{- 2}

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Solution

The correct option is B $\frac{40}{3} {m s}^{- 2}$
Given,

$r = 120 m$

$v = 40 m / s$

Centripetal acceleration of the train,

$a_{c} = \frac{v^{2}}{r}$

$a_{c} = \frac{40 \times 40}{120}$

$a_{c} = \frac{40}{3} m / s^{2}$

The correct option is B.

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A train is travelling at constant speed of 40ms−1 on a circular track of radius 120 m. Centripetal acceleration of the train is:

The correct option is B 403ms−2Given,r=120mv=40m/sCentripetal acceleration of the train,ac=v2rac=40×40120ac=403m/s2The correct option is B.

A train is travelling at constant speed of $40 {m s}^{- 1}$ on a circular track of radius 120 m. Centripetal acceleration of the train is:

The correct option is B $\frac{40}{3} {m s}^{- 2}$
Given,

$r = 120 m$

$v = 40 m / s$

Centripetal acceleration of the train,

$a_{c} = \frac{v^{2}}{r}$

$a_{c} = \frac{40 \times 40}{120}$

$a_{c} = \frac{40}{3} m / s^{2}$

The correct option is B.