A train is travelling at the speed of $96 k m / h r$ .
It takes $3$ seconds to enter a tunnel and $30$ seconds more to pass through it completely. What are the lengths of the train and the tunnel ?

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Solution

Given a train travelling
$96$ km/hr converting to m/s
i.e. $\frac{96000}{3600} = \frac{80}{3} m / s$
The length of train
$= \frac{80}{3} \times 3 = 80 m$
Length of tunnel
$= \frac{80}{3} \times 33 = 880 m$

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A train is travelling at the speed of 96 km/hr.It takes 3 seconds to enter a tunnel and 30 seconds more to pass through it completely. What are the lengths of the train and the tunnel ?

Given a train travelling96 km/hr converting to m/si.e. 960003600=803m/sThe length of train=803×3=80mLength of tunnel=803×33=880m

A train is travelling at the speed of $96 k m / h r$ .
It takes $3$ seconds to enter a tunnel and $30$ seconds more to pass through it completely. What are the lengths of the train and the tunnel ?

Given a train travelling
$96$ km/hr converting to m/s
i.e. $\frac{96000}{3600} = \frac{80}{3} m / s$
The length of train
$= \frac{80}{3} \times 3 = 80 m$
Length of tunnel
$= \frac{80}{3} \times 33 = 880 m$