Question

A train leaves Delhi at 10 a.m an reaches Jaipur at 4 p.m on the same day. Another train leaves Jaipur at 12 p.m and reaches Delhi at 5 p.m on same day. What is the time of the day (approximately) when the two trains will meet?

• A. 1:42 p.m
• B. 1:27 p.m
• C. 04 p.m
• D. 1:49 p.m

Answer 1

Answer: (D)

1:49 p.m

Assuming their velocities to be uniform throughout

the journey, the Delhi train takes 6 hours and the

Jaipur to Delhi train takes 5 hours reaching.

The distance between two stations be x kms.

The one heading Jaipur nears Jaipur = $\frac{2x}{6}kms$, from

when one heading Delhi starts.

The two trains have to cover the relative distance

of $\{x.(x/3\left)\right\}=\left(2x/3\right)$.

The relative velocity over the journey = $\frac{x}{6}+\frac{x}{5}$

$=\frac{5x+6x}{30}$

$=11x/30$

covering the relative distance of $\left(2x/3\right)$ time taken

will be $\Rightarrow \left(\frac{2x}{3}\right)\left(\frac{11x}{30}\right)$

$=20/11$ hours

= 1 hr 49 minutes.

$\therefore$ The two trains will meet at 1 hr 49 minutes p.m

So, the answer is "1 hour 49 minutes p.m"