A train moves from one station to another in 2 hours time, its speed during the motion is shown in graph above. The maximum acceleration during the journey and distance covered during the time interval from 0.75 hour to 1.00 hour are
A
60kmhr−2,100km
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B
160kmhr−2,10km
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C
10kmhr−2,10km
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D
260kmhr−2,1km
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Solution
The correct option is B160kmhr−2,10km Maximum acceleration will occur in the region with maximum slope. From the given curve region CD is having the maximum curve. Thus, maximum acceleration=changeinvelocitychangeindistance=60−200.25=160 Now, total area under the curve between 0.75 to 1.00 hrs is given by (12×0.25×40)+(20×0.25)=10km