A train moves towards a stationary observer with speed 34 m/s. The train sounds a whistle and its frequency registered by the observer is $f_{1}$ . If the train's speed is reduced to 17 m/s, the frequency registered is $f_{2}$ . If the speed of sound is 340 m/s then the ratio $\frac{f_{1}}{f_{2}}$ is :

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Solution

The correct option is D

$f_{1} = f (\frac{v}{v - v_{s}})$

$f_{1} = f (\frac{340}{340 - 34}) = f (\frac{340}{306})$

and $f_{2} = f (\frac{340}{340 - 17}) = f (\frac{340}{323})$

$∴ \frac{f_{1}}{f_{2}} = (\frac{323}{306}) = \frac{19}{18}$

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. The train sounds a whistle and its frequency registered is

f_{1}

. If the train’s speed is reduced to

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, the frequency registered is

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. If the speed of sound is

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A train moves towards a stationary observer with speed 34 m/s. The train sounds a whistle and its frequency registered is f1. If the train’s speed is reduced to 17 m/s, the frequency registered is $f_{2}$ . If the speed of sound is 340 m/s then the ratio $\frac{f_{1}}{f_{2}}$ is

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A train moves towards a stationary observer with speed 34 m/s. The train sounds a whistle and its frequency registered by the observer is f1. If the train's speed is reduced to 17 m/s, the frequency registered is f2 . If the speed of sound is 340 m/s then the ratio f1f2 is :

The correct option is D f1=f(vv−vs) f1=f(340340−34)=f(340306) and f2=f(340340−17)=f(340323) ∴f1f2=(323306)=1918

The correct option is D

$f_{1} = f (\frac{v}{v - v_{s}})$

$f_{1} = f (\frac{340}{340 - 34}) = f (\frac{340}{306})$

and $f_{2} = f (\frac{340}{340 - 17}) = f (\frac{340}{323})$

$∴ \frac{f_{1}}{f_{2}} = (\frac{323}{306}) = \frac{19}{18}$