The correct option is
A 10 minutes This question can be solved by alligation.
Speed when moving = 60 km/h
Speed when at rest = 0 km/h
Average speed = 50 km/h (Given)
Hence, time ratio = 5 : 1.
∴ In one hour, train moved for 50 min and rested for 10 min.
Alternate Approach: For this type question, take the LCM of speeds and assume the LCM as the distance.
then the time taken @ speed of 60km/hr
=30060= 5 hrs
again the time taken @ speed of 50 km/hr
=30050 = 6hrs
Thus we see that in place of 5 hrs train takes 6 hours. It means the train takes 1 hour extra and this one hour is stopping period in the total time of 6 hours. Thus in 6 hours, train halts for 1 hour. So in 1 hour, the train will stop for
16 hours or 10 minutes.
Alternatively: (short cut)
Halting (or stopping) time
=(1−slower speedfaster speed)hours =1−5060=1060=16hours = 10 minutes
(
∵ 1 hour = 60 minutes)