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Question

A train of length 180 m crosses a man standing on a platform in 12 seconds and cross another train coming from opposite direction in 12 sec. If the second train running at 2/3 rd speed of the firstthen find the length of the second train?

A
56
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B
120
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C
20
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D
44
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Solution

The correct option is B 120
Length of the first train=180m

Time taken by the train to cross the man standing on the platform=12s

Speed of the first train=18012

=15m/s

Speed of the second train=23×15

=10m/s

Relative speed=15+10

=25m/s
Let the length of the train be y metres.

Distance=Speed×time

y+180=25×12

y+180=300

y=300180
y=120
So, the length of the second train=120m

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