Question

A train of mass $M=\pi kg$ is moving on a circular track of radius ${}^{\prime }{R}^{\prime }$ with constant speed $V=2m/s$. The length of the train is half of the perimeter of the track. The linear momentum of the train will be

Answer 1

Linear momentum will be $mv=2\pi$

Angular momentum $=mvr$

length of the train= $2$ length

parameter $=2\pi R=2$ length

$r=\frac{2}{\pi }$

and angular momentum $=\pi \times 2\times \frac{2}{R}=\frac{4\pi }{R}$