A train overtakes two persons, who are walking in the same direction in which the train is going at the rate of 2km/hr and 4 km/hr, and passes them completely in 9 and 10 seconds respectively. The length of the train is –

2000m

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3000m

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4000m

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5000m

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Solution

The correct option is B
3000m

\frac{L}{V-2}=\frac{9}{60}\Rightarrow 9V-18 \\
and, \frac{L}{V-4}=\frac{10}{60}\Rightarrow 60L=10V-40 \\
\Rightarrow 9V-18=10V-40 \\
V=22\\
Then, L=\frac{9\times22-18}{60}=\frac{198-18}{60} \\
\frac{180}{60}=3Km=3000meters

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A train overtakes two persons, who are walking in the same direction in which the train is going at the rate of 2km/hr and 4 km/hr, and passes them completely in 9 and 10 seconds respectively. The length of the train is –

The correct option is B 3000m \frac{L}{V-2}=\frac{9}{60}\Rightarrow 9V-18 \\ and, \frac{L}{V-4}=\frac{10}{60}\Rightarrow 60L=10V-40 \\ \Rightarrow 9V-18=10V-40 \\ V=22\\ Then, L=\frac{9\times22-18}{60}=\frac{198-18}{60} \\ \frac{180}{60}=3Km=3000meters

The correct option is B
3000m

\frac{L}{V-2}=\frac{9}{60}\Rightarrow 9V-18 \\
and, \frac{L}{V-4}=\frac{10}{60}\Rightarrow 60L=10V-40 \\
\Rightarrow 9V-18=10V-40 \\
V=22\\
Then, L=\frac{9\times22-18}{60}=\frac{198-18}{60} \\
\frac{180}{60}=3Km=3000meters