A train passes two persons walking in the same direction at a speed of 3 km/hr and 5 km/hr respectively in 10 seconds and 11 seconds. The speed of the train is
A
28 km/hr
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
27 km/hr
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
25 km/hr
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
24 km/hr
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C25 km/hr Distance covered by the first person in 10 seconds =[(3×518)×10]m=253m Distance covered by the second person in 11 seconds =[(5×518)×11]m=27518m ∴ The train travels a distance =27518−253=12518m in (11−10)=1 second. ∴ Speed of the train =(12518×185) km/hr =25 km/hr.