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Question

A train running at 108 km h1 towards east whistles at a dominant frequency of 600 Hz. Speed of sound in air is 340 m/s. What frequency will a passenger sitting near the open window hear ? (b) What frequency will a person standing near the track hear whom the train has just passed ? (c) A wind starts blowing towards east at a speed of 36 km h1. Calculate the frequencies heard by the passenger in the train and by the person standing near the track.

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Solution

(a)Velocity of passenger with respect to the train is zero. So, Required frequecny =500 Hz

(b)Frequency heard by the person standing near the track,

n=v+v0v+vs×n0

=340+0340+30×500=459Hz

(c)When the wind starts blowing towards east.

Frequency heard by passenger is unaffected.

But frequency heard by passenger is unaffected.

But frequency heard by person stadly near the track,

n=(vvair)(vvair)+vs×n0

=(34010)(34010)+30×500

=458 Hz


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