A train running at 2 by 5 of its own speed reached a place in 15 minutes. In what time will it reach there running at its own speed?

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Solution

let X be the distance coverd y be its orginal speed

the distance / speed = time

X/(2/5)Y = 15 min

X/15 * 5/2 = Y

5X/30 = Y

X/6 = Y

so time taken if with its orginal speed is

X/X/6 = 6 min

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A train running at 2 by 5 of its own speed reached a place in 15 minutes. In what time will it reach there running at its own speed?

let X be the distance coverd y be its orginal speed the distance / speed = time X/(2/5)Y = 15 min X/15 * 5/2 = Y 5X/30 = Y X/6 = Y so time taken if with its orginal speed is X/X/6 = 6 min

let X be the distance coverd y be its orginal speed

the distance / speed = time

X/(2/5)Y = 15 min

X/15 * 5/2 = Y

5X/30 = Y

X/6 = Y

so time taken if with its orginal speed is

X/X/6 = 6 min