A train running at $30 m / s$ comes to rest at uniform deceleration within $44 s$ . The distance travelled by train before coming to rest is

654 m

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660 m

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612 m

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630 m

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Solution

The correct option is B $660 m$
Initial velocity of the train, $u$ = $30 m / s$

Final velocity of the train, $v$ = $0 m / s$

Time taken to stop, $t$ = $44 s$
Let the distance travelled before coming to rest be ‘ $s$ ’

Let the uniform deceleration be ‘ $a$ ’

$a$ = $\frac{v - u}{t}$ = $\frac{0 - 30}{44}$

$a$ = $\frac{- 30}{44}$
where negative sign denotes that the direction of acceleration is opposite to that of motion.

Applying equation of motion

$v^{2} = u^{2} + 2 a s$

Putting the values we get,

$s = 660 m$

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A train running at 30 m/s comes to rest at uniform deceleration within 44 s. The distance travelled by train before coming to rest is

A train running at $30 m / s$ comes to rest at uniform deceleration within $44 s$ . The distance travelled by train before coming to rest is