A train running at $\frac{5}{8}$ of its own speed reached the destination in 16 hours, how much time could be saved if the train would have run at its own speed?

4 hours

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5 hours

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6 hours

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7 hours

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None of these

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Solution

The correct option is C
6 hours

New speed = $\frac{5}{8}$ of normal speed

So, new time will be = $\frac{8}{5}$ of normal time. (Inverse relation)

As $\frac{8}{5}$ of normal time is = 16 hours

So, normal time = (16 $\times$ $\frac{5}{8}$ ) = 10 hrs

So time saved = 16 - 10 = 6 hours

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A train running at 58 of its own speed reached the destination in 16 hours, how much time could be saved if the train would have run at its own speed?

The correct option is C 6 hours New speed = 58 of normal speed So, new time will be = 85 of normal time. (Inverse relation) As 85 of normal time is = 16 hours So, normal time = (16 × 58) = 10 hrs So time saved = 16 - 10 = 6 hours

A train running at $\frac{5}{8}$ of its own speed reached the destination in 16 hours, how much time could be saved if the train would have run at its own speed?

The correct option is C
6 hours

New speed = $\frac{5}{8}$ of normal speed

So, new time will be = $\frac{8}{5}$ of normal time. (Inverse relation)

As $\frac{8}{5}$ of normal time is = 16 hours

So, normal time = (16 $\times$ $\frac{5}{8}$ ) = 10 hrs

So time saved = 16 - 10 = 6 hours