A train running at the speed of $60$ kmph crosses a pole in $9$ seconds. What is the length of the train?

120 metres

No worries! We‘ve got your back. Try BYJU‘S free classes today!

180 metres

No worries! We‘ve got your back. Try BYJU‘S free classes today!

150 metres

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

270 metres

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 150 metres
Time $= 9$ seconds
Speed $= (60 \times \frac{5}{18}) m / s e c = (\frac{50}{3}) m / s e c$
$∴$ Speed $= \frac{Distance}{Time}$

Length of the train (Distance) = (Speed $\times$ Time) = $(\frac{50}{3} \times 9) m = 150 m .$

Suggest Corrections

176

Similar questions

Q. A train running at the speed of

60

km/hr crosses a pole in

9

seconds. What is the length of the train?

Q. A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?

Q. A train is running at a speed of 60 kmph crosses a platform double its length in 32.4 seconds. What is the length of the platform?

A train running at a speed of 84 kmph crosses a man running at a speed of 6 kmph in the opposite direction in 4 seconds. What is the length of the train (in meters)?

A train crosses another train which is running in the opposite direction in `t' seconds. What is the speed of the train?

I. Both the trains are running at the same speed and have the same length.

II. One of the trains cross a pole in 10 seconds.

Join BYJU'S Learning Program

A train running at the speed of 60 kmph crosses a pole in 9 seconds. What is the length of the train?

The correct option is B 150 metresTime =9 seconds Speed =(60×518) m/sec=(503)m/sec∴ Speed =DistanceTime Length of the train (Distance) = (Speed × Time) = (503×9) m=150 m.

A train running at the speed of $60$ kmph crosses a pole in $9$ seconds. What is the length of the train?

The correct option is B 150 metres
Time $= 9$ seconds
Speed $= (60 \times \frac{5}{18}) m / s e c = (\frac{50}{3}) m / s e c$
$∴$ Speed $= \frac{Distance}{Time}$

Length of the train (Distance) = (Speed $\times$ Time) = $(\frac{50}{3} \times 9) m = 150 m .$