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Question

A train S1 moving with a uniform velocity of 108 km/h approaches another train S2 standing on a platform. An observer O moves with a uniform velocity of 36 km/h towards S2 as shown in figure. Both the trains are blowing whistles of same frequency 120 Hz. When O is 600 m away from S2 and distance between S1 and S2 is 800 m, the number of beats heard by O is . (Speed of the sound =330 m/s)


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Solution

Speed of sound =330m/s
Number of beats = frequency difference between the frequency observed by observer from S1 and S2, fb=120[(330+10cos53o33030cos37o)(330+10330)]=120[3363063433]=8.128Hz


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