A train starting from a railway station and moving with uniform acceleration, attain a speed of $40 k m h^{- 1}$ in $10$ minutes. Its acceleration is:

18.5 m s^{- 2}

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1.85 c m s^{- 2}

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18.5 c m s^{- 2}

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1.85 m s^{- 2}

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Solution

The correct option is B $1.85 c m s^{- 2}$
$a c c = \frac{v_{2} - v_{1}}{t} = \frac{v_{2} - 0}{t} = \frac{40 - 0}{10 \times 60}$

$= \frac{40 \times 1000 \times 100}{3600 \times 10 \times 60} c m s^{- 2}$

$= 1.85 c m s^{- 2}$

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