A train starting from a stationary position and moving with uniform acceleration attain a speed of 36km/h in 10 minutes.Find its acceleration.

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Solution

As it moves from stationary position initial speed = 0
it attain a speed = 36km/h(final speed)= 10m/s
time taken= 10min=10*60=600sec

so by v=u+at
10=0+a(600)
a=1/60=0.0166m/s²

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Q. A train starting from rest position and moving with uniform acceleration attains a speed of 36km/hr in 10 min.find it's acceleration?

Q. (a) Derive the formula :

s = u t + \frac{1}{2} a t^{2}

, where the symbols have usual meanings.
(b) A train starting from stationary position and moving with uniform acceleration attains a speed of 36 km per hour in 10 minutes. Find its acceleration.

(a) Derive the formula: $s = u t + \frac{1}{2} a t^{2}$ , where the symbols have usual meanings.

(b) A train starting from stationary position and moving with uniform acceleration attains a speed of 36 km per hour in 10 minutes. Find its acceleration.

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A train starting from a stationary position and moving with uniform acceleration attain a speed of 36km/h in 10 minutes.Find its acceleration.

As it moves from stationary position initial speed = 0 it attain a speed = 36km/h(final speed)= 10m/s time taken= 10min=10*60=600sec so by v=u+at 10=0+a(600) a=1/60=0.0166m/s²

As it moves from stationary position initial speed = 0
it attain a speed = 36km/h(final speed)= 10m/s
time taken= 10min=10*60=600sec

so by v=u+at
10=0+a(600)
a=1/60=0.0166m/s²