Question

A train starting from rest attains a velocity of $72km/h$ in $5$ min. Assuming the acceleration is uniform; Find the acceleration and distance travelled by train for this velocity.

Answer 1

v=u+at

a=(v-u)/t -----------(1)

v=72 km/h

=20m/s

u=0

t=5*60 sec =300sec

by putting values of v,u,t in (1)

a=1/15 m/s²

s=ut +(1/2)at²

=0+(1/2)(1/15)(300)(300)

=3km