Question

A train starting from rest moves with a uniform acceleration of 0.2 m/s² for 5 minutes. Calculate the speed acquired and the distance travelled in this time.

Answer 1

We have to find the distance travelled as well as final velocity of the train. We have the following information given,
Initial velocity, (u) = 0 m/s
Acceleration for the entire journey, (a) = 0.2 m/s²
Time taken,
(t) = (5) (60) s
= 300 s
So, we can find the final velocity using the relation,
v = u + at
Therefore, final velocity of the train is,
v = 0 + (0.2)(300)
= 60 m/s
We can calculate the distance travelled by the train, using the 2^nd equation of motion,
$s=ut+\frac{1}{2}a{t}^2$
Put the values in above equation to find the distance travelled,
$$\begin{gathered} \left(s\right)=0\left(300\right)+\frac{1}{2}(0.2)(300{)}^2 \\ =(9000)\mathrm{m} \\ =\boxed{9\mathrm{km}} \end{gathered}$$