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Standard XII

Mathematics

Definition of Functions

A train start...

Question

A train starting from rest, picks up a speed of $20 m s^{- 1}$ in 200 s. It continues to move at the same speed for the next 500 s. It is then brought to rest in the next 100 s. Find total distance covered.

3 k m

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13 k m

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10 k m

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25 k m

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Solution

The correct option is B $13 k m$
$s = s_{1} + s_{2} + s_{3} = t o t a l d i s t a n c e c o v e r e d = \frac{1}{2} \times 200 \times 20 + 500 \times 20 + \frac{1}{2} \times 100 \times 20 = 2000 + 10000 + 1000 = 13000 m = 13 k m$

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A train starting from rest, picks up a speed of 20ms−1 in 200 s. It continues to move at the same speed for the next 500 s. It is then brought to rest in the next 100 s. Find total distance covered.

The correct option is B 13kms=s1+s2+s3=totaldistancecovered=12×200×20+500×20+12×100×20=2000+10000+1000=13000m=13km

A train starting from rest, picks up a speed of $20 m s^{- 1}$ in 200 s. It continues to move at the same speed for the next 500 s. It is then brought to rest in the next 100 s. Find total distance covered.

The correct option is B $13 k m$
$s = s_{1} + s_{2} + s_{3} = t o t a l d i s t a n c e c o v e r e d = \frac{1}{2} \times 200 \times 20 + 500 \times 20 + \frac{1}{2} \times 100 \times 20 = 2000 + 10000 + 1000 = 13000 m = 13 k m$