A train starting from rest position and moving with uniform acceleration attains a speed of 36km/hr in 10 min.find it's acceleration?

Open in App

Solution

If a train starts from stationary position then initial velocity of train = 0

moving uniform acceleration means constant acceleration .

given ,
final velocity ( V) = 36 km/h = 36× 5/18
= 10m/s

time taken = 10 minutes = 10× 60sec
= 600sec

use kinematics equation ,

V = u + at

10 = 0 + a × 600

a = 10/600 = 1/60 m/s²

a = 0.1667 × 10^-1 m/s² = 1.67 × 10^-2 m/s²

Suggest Corrections

Similar questions

Q. A train starting from rest position and moving with uniform acceleration attains a speed of 36km/hr in 10 min.find it's acceleration?

A train starting from a stationary position and moving with uniform acceleration attain a speed of 36km/h in 10 minutes.Find its acceleration.

Q. A train starting from a railway station and moving with uniform acceleration attains a speed of

40 k m h r^{- 1}

10 m i n u t e s

. Find its acceleration in the units of

m s^{- 2}

Q. (a) Derive the formula :

s = u t + \frac{1}{2} a t^{2}

, where the symbols have usual meanings.
(b) A train starting from stationary position and moving with uniform acceleration attains a speed of 36 km per hour in 10 minutes. Find its acceleration.

(a) Derive the formula: $s = u t + \frac{1}{2} a t^{2}$ , where the symbols have usual meanings.

(b) A train starting from stationary position and moving with uniform acceleration attains a speed of 36 km per hour in 10 minutes. Find its acceleration.

Join BYJU'S Learning Program