Question

A train starting from a railway station and moving with uniform acceleration attains a speed of $40km{h}^{-1}$ in $10minutes$. Find its acceleration in the units of $m{s}^{-2}$.

Answer 1

Step 1: Given data

Initial speed, $u=0m{s}^{-2}$

Final velocity, $v=40km{h}^{-1}=40\times \frac{5}{18}=\frac{100}{9}m{s}^{-1}$

Time, $t=10minutes=600seconds$

Step 2: Formula used

$v=u+at$

Where “a” is the acceleration.

Step 3: Formula used and calculation

Using the first equation of motion

$$\begin{gathered} v=u+at \\ \Rightarrow \frac{100}{9}m{s}^{-1}=0+600s\times a \\ \Rightarrow a=\frac{100}{9\times 600}m{s}^{-2} \\ \Rightarrow a=0.0185m{s}^{-2} \end{gathered}$$

Hence, the acceleration of the train is $0.0185m{s}^{-2}$.